Python Coding Challenge - Question with Answer (ID -070426)

 

Code Explanation:

1. Global Variable Declaration

x = 14

A variable x is created in the global scope.

Its value is 14.

This means x can be accessed anywhere in the program unless shadowed locally.

⚙️ 2. Function Definition

def func():

A function named func is defined.

No parameters are passed to this function.

🖨️ 3. First Statement Inside Function

print(x)

Python looks for x inside the function first (local scope).

But notice: later in the function, x = 5 exists.

Because of that assignment, Python treats x as a local variable throughout the function.

👉 Important rule:

If a variable is assigned anywhere inside a function, Python considers it local to that function (unless declared global).

❗ 4. Local Assignment

x = 5

This creates a local variable x inside func.

It does NOT affect the global x.

🚨 5. Function Call

func()

When the function runs:

Python sees x = 5 → decides x is local

Then tries print(x) BEFORE assigning it

💥 6. Error Occurs

You will get:

UnboundLocalError: local variable 'x' referenced before assignment

Why?

Python thinks x is local

But print(x) tries to use it before it's assigned

Final Output:

Error

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